## Ball Earth Curvature Chart

IF the earth is a globe, and is 25,000 English statute miles in circumference, the surface of all standing water must have a certain degree of convexity–every part must be an arc of a circle. From the summit of any such arc there will exist a curvature or declination of 8 inches in the first statute mile. In the second mile the fall will be 32 inches; in the third mile, 72 inches, or 6 feet, as shown in the following diagram:

Let the distance from T to figure 1 represent 1 mile, and the fall from 1 to A, 8 inches; then the fall from 2 to B will be 32 inches, and from 3 to C, 72 inches. In every mile after the first, the curvature downwards from the point T increases as the square of the distance multiplied by 8 inches. The rule, however, requires to be modified after the first thousand miles. 1 The following table will show at a glance the amount of curvature, in round numbers, in different distances up to 100 miles.^{[4]}

(note how many times 666 shows up)

Statute Miles Away | Math | = Drop |
---|---|---|

1 | 1 x 1 x 8 = | 8 Inches |

2 | 2 x 2 x 8 = | 32 Inches |

3 | 3 x 3 x 8 / 12 = | 6 Feet |

4 | 4 x 4 x 8 / 12 = | 10.6 Feet |

5 | 5 x 5 x 8 / 12 = | 16.6 Feet |

6 | 6 x 6 x 8 / 12 = | 24 Feet |

7 | 7 x 7 x 8 / 12 = | 32.6 Feet |

8 | 8 x 8 x 8 / 12 = | 42.6 Feet |

9 | 9 x 9 x 8 / 12 = | 54 Feet |

10 | 10 x 10 x 8 / 12 = | 66.6 Feet |

20 | 20 x 20 x 8 / 12 = | 266.6 Feet |

30 | 30 x 30 x 8 / 12 = | 600 Feet |

40 | 40 x 40 x 8 / 12 = | 1,066.6 Feet |

50 | 50 x 50 x 8 / 12 = | 1,666.6 Feet |

60 | 60 x 60 x 8 / 12 = | 2,400 Feet |

70 | 70 x 70 x 8 / 12 = | 3,266.6 Feet |

80 | 80 x 80 x 8 / 12 = | 4,266.6 Feet |

90 | 90 x 90 x 8 / 12 = | 5,400 Feet |

100 | 100 x 100 x 8 / 12 = | 6,666.6 Feet |

120 | 120 x 120 x 8 / 12 = | 9,600 Feet |

Patrick PhillipsDecember 17, 2015 at 9:33 pmA few days ago I was standing at the port of Anchorage in Anchorage Alaska. I work for the local power company here. I took a picture of Denali. . About 140 miles away. I asked my surveyors about the formulas to figure the curvature from Anchorage to Denali. . They could not. If I could see Denali at all. . Maybe I should only be able to see 3000 ft of it. I got a pic of literally the whole mountain. The curvature should be about 14000 ft. Is that correct. ?

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Angelo NMay 29, 2016 at 8:52 pmThe 8 inches x squared miles doesn’t take in consideration the elevation of the observer.

This formula is USELESS.

If you are 6 feet tall, the drop related to a distance of 5 miles is roughly 2 feet.

If your obsarvation point is 20 feet high, you don’t have any drop for the same distance.

https://dizzib.github.io/earth/curve-calc/?d0=5&h0=20&unit=imperial

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arielJuly 7, 2016 at 12:05 pmANGELO, no is not usless. The formula is based in about 5.8 ft eye point level.

Use the link your share, (Dizzib) and do your own reserch.

First buy a Nikon coolpix P900, go to the beach, so you are sure altitude is zero, and loom the horizon, place the camera 5.8 ft (to avoid the sea waves) and take a look. Horizon should be only up to 2 to 3 miles, but because the earth is flat, you’ll see over the horizon. You’ll be amazed hoe far you can see.

The truth shall set you free…..

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Ricky HickyMay 31, 2017 at 7:18 amSo why can’t you see further than 3 miles, on the beach, at the sea shore, looking out to sea?…………ever.

.

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Ted sagoNovember 21, 2016 at 1:30 pmA clock face of 24k miles circumference (sp?) would give us 2k miles for every hour, you can clearly see the curve from,say,one o clock to two, how high would you have to go to see 2k miles of horizon?

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LibertarianJanuary 7, 2017 at 7:36 pmAnother way of calculating this formula is multiplying the distance in miles squared by .666 which saves the step of dividing by 12 and also reveals the true nature of this global conspiracy .Anyone can easily prove there is zero curve. I filmed Catalina standing in the ocean from over 48 miles away. (43 to midpoint of island) and it is clearly all visible when most of it should be behind the supposed curve. https://www.youtube.com/watch?v=7GbB6fnSP6s

And more incredibly I filmed Mammoth which is 300 miles from my house. It is 7,880 feet high. My elevation is 442 feet.It should be behind 9.5 miles of curve. I will be editing and uploading that video.

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KyleMarch 23, 2017 at 7:20 pmThe earth is so flat it makes some people mad. Zero curve found

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Ricky HickyMay 31, 2017 at 8:03 amMore fake news.

…..your elevation is 442 feet. It should be behind 9.5 miles of curve…….at sea level! How much curve does the math say there should be at 442 feet?

Answer…..a great deal more than your 9.5 miles.

Get real you flat heads.

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